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.7x^2-3.5x-25=0
a = .7; b = -3.5; c = -25;
Δ = b2-4ac
Δ = -3.52-4·.7·(-25)
Δ = 82.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3.5)-\sqrt{82.25}}{2*.7}=\frac{3.5-\sqrt{82.25}}{1.4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3.5)+\sqrt{82.25}}{2*.7}=\frac{3.5+\sqrt{82.25}}{1.4} $
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